Question

A game of chance consists of spinning an arrow which comes to rest pointing at one of the number 1,2,...8 and these are equally outcome s .what is the probability that it will point at ( i) 8 ( ii) an odd number (iii) a number greater than 2 (iv) a number less than 9

Answer 1

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(i). favourable outcomes
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total outcomes

1
-----
8

(ii). 3
----
8

(iii). 6
---
8

(iv). 1

Answer 2

Answer:

Ans. Out of 8 numbers, an arrow can point any of the numbers in 8 ways.

Total number of favourable outcomes = 8

(i) Favourable number of outcomes = 1

Hence, P (arrow points at 8) =

(ii) Favourable number of outcomes = 4

Hence, P (arrow points at an odd number) =

(iii) Favourable number of outcomes = 6

Hence, P (arrow points at a number > 2) =

(iv) Favourable number of outcomes = 8

Hence, P (arrow points at a number < 9) = =1