Question

A game of chance consists of spinning an arrow which
is equally likely to come to rest pointing to one of the
number 1, 2, 3,..., 12 as show in fig. what is the
probability that it will point to :
(0) 107 (ii) an odd number (iii) a number which
Is multiple of 3 ? (iv) an even number?


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Answer 1

Step-by-step explanation:

1. 0/12 equal to 0. 2.6/12 equal to 1/2. 3.4/12 equal to 1/3.

4. 6/12 equal to 1/2

Answer 2

Answer:

Ans. Out of 8 numbers, an arrow can point any of the numbers in 8 ways.

Total number of favourable outcomes = 8

(i) Favourable number of outcomes = 1

Hence, P (arrow points at 8) =

(ii) Favourable number of outcomes = 4

Hence, P (arrow points at an odd number) =

(iii) Favourable number of outcomes = 6

Hence, P (arrow points at a number > 2) =

(iv) Favourable number of outcomes = 8

Hence, P (arrow points at a number < 9) = =1