Question

A game of chance consists of spinning and arrow on a circle board divided into 8 equal parts which comes to rest. At one of the number 1 2 3 4 5 6 7
8 which are equally likely outcomes what is the probability that the arrow will. At first and odd number second at a number greater than 3 on number less than 9

Answer 1

↑ Here is your answer ↓
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1. An odd number 

Total outcomes = 8
Odd numbers = 4

So, the probability is $\frac{4}{8} = 0.5$

2. At a number greater than 3 or number less than 9

Total outcomes = 8
Favorable outcomes = 5

So, the probability is $\frac{5}{8} = 0.625$

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The following attachment is only for your understanding:

Answer 2

Ans. Out of 8 numbers, an arrow can point any of the numbers in 8 ways.

Total number of favourable outcomes = 8

(i) Favourable number of outcomes = 1

Hence, P (arrow points at 8) =

(ii) Favourable number of outcomes = 4

Hence, P (arrow points at an odd number) =

(iii) Favourable number of outcomes = 6

Hence, P (arrow points at a number > 2) =

(iv) Favourable number of outcomes = 8

Hence, P (arrow points at a number < 9) = =1