Math, asked by kamajusanthi, 9 months ago

a game of chances consists of spinning arrows to rest pointing at one of the numbers 1,2,3,4,5,6,7,8 and they are equally likely outcome . what is the probability that it will be point at
1. a number less than 7
2. a composite number
3. a factor of 8
4. a multiple of 8​

Answers

Answered by kanimozhi15111
0

Answer:

1)event=no less than 7

p[e]=sample space=1,2,3,4,5,6

probability=6/8=3/4

2)event=a composite number

sample space=4,6,8

probability=3/8

3)a factor of 8=1,2,4,8

probability=4/8=1/2

4)a mulitple of 8=1,2,4,8

probability=4/8=1/2

Answered by Anonymous
0

Answer:

Ans. Out of 8 numbers, an arrow can point any of the numbers in 8 ways.

Total number of favourable outcomes = 8

(i) Favourable number of outcomes = 1

Hence, P (arrow points at 8) =

(ii) Favourable number of outcomes = 4

Hence, P (arrow points at an odd number) =

(iii) Favourable number of outcomes = 6

Hence, P (arrow points at a number > 2) =

(iv) Favourable number of outcomes = 8

Hence, P (arrow points at a number < 9) = =1

Similar questions