Question

A game room has a perimeter of 70 ft. The length is five more than twice the width. How many ft2 of new carpeting should be ordered?

Answer 1

Step-by-step explanation:

Answer:-

Given:-

• Perimeter = 70 feet
• Length = 5 + 2 times the breadth.

To find:-

Area of the game room.

Let's Do!

What we need to do is:-

• Consider the breadth as x.
• So length is 2x.

$\sf{Perimeter = 2(L+B)}$

$\sf{70 = 2(x+2x+5)}$

$\sf{35 = 3x+5}$

$\sf{30 = 3x}$

$\sf{10 = x}$

Now,

• Length is 10 × 2 +5 = 25 feet
• And breadth is 10feet.

Area = Length × Breadth

= 10 × 25

$\boxed{\sf{Area = 250 ft^2}}$

Note:-

• Take the ratio constant as x.
• 2 x is taken as it was given that the length is twice its breadth.
• A special vigil on the units.
• And number us greater than constants.

Answer 2

Answer:

★ ANSWER :

250ft² of new carpeting should be ordered.

Step-by-step explanation:

★ QUESTION :

A game room has a perimeter of 70 ft. The length is five more than twice the width. How many ft² of new carpeting should be ordered ?

★ CONCEPT USED :

• Perimeter of rectangle = 2(Length + Breadth)
• Area of rectangle = Length × Breadth
• Breadth = Width

★ GIVEN :

• Perimeter = 70 ft
• Length = (2 × Breadth) + 5

★ TO FIND :

• Area of rectangle = ?

★ SOLUTION :

Let the of breadth rectangle be b.

Therefore , length of rectangle = (2 × Breadth) + 5

Therefore , length of rectangle = 2b + 5

Now ,

Perimeter of rectangle = 2(Length + Breadth)

→ 70ft = 2( 2b + 5 + b)

→ 70 = 2(3b + 5)

→ 70/2 = 3b + 5

→ 35 = 3b + 5

→ 35 - 5 = 3b

→ 30 = 3b

→ 30/3 = b

→ 10 = b

→ b = 10ft

Therefore , Breadth = 10ft

Length of rectangle = (2 × Breadth) + 5

Length of rectangle = (2 × 10) + 5

Length of rectangle = 20 + 5

Length of rectangle = 25ft

Area of carpet = Area of rectangle

Area of rectangle = Length × Breadth

Area of rectangle = 25ft × 10ft

Area of rectangle = 250ft²

Therefore , 250ft² of new carpeting should be ordered.

★ ANSWER :

250ft² of new carpeting should be ordered.