Question

a garden bed is shown below, it is a rectangle with semi circular ends. it has a concrete circular fountain the centre as shown. Grass is grown in the garden bed at all places except the central fountain region. the area of the concrete circular fountain at the centre is​



Plz help me , it's my humble request

Answer 1

Answer:

Total area of the garden = Area of the rectangular portion + The sum of the areas of the pair of semi-circles

=l.b+2×

2

1

πr

2

=(13×7)m

2

+(

2×

2

1

×

7

22

×3.5×3.5

)m

2

=(91+38.5)m

2

=129.5m

2

.

Perimeter of the garden =2× length of rectangular portion + circumference of the circle

=(

2×13+2×

7

22

×3.5

)m

=(26+22)m=48m.

Answer 2

Given:

Diameter of the semi-circular ends = 14m

Length of the whole garden = 35m

To find:

The area of the concrete circular fountain.

Solution:

The diameter of the semi-circular ends is given as 14m. Both these semi-circular ends have the same diameter. Let $d$ be the diameter, then its radius, $r$ is the half of diameter.

$d=2r$

∴ $r=\frac{d}{2}=\frac{14}{2}=7m$

The circular fountain at the centre has the same diameter as that of the semi-circular ends. Hence, its radius is also the same.

Area of the circular fountain region = Area of a circle

$Area=\pi r^{2}$

$Area=\frac{22}{7}*7*7$

$Area=154m^{2}$

Hence, option (c) is the correct answer.

The area of the concrete circular fountain at the centre is 154m². Option (c) is the right answer.