A garden has dimensions 75m by 55m. Two cross roads each of width 5m, perpendicular to each other, run through the centre of the garden. Find the area of the cross roads.
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Answerwidth =5 m
Answerwidth =5 mlength of first parallel road 70 m
Answerwidth =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.m
Answerwidth =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m
Answerwidth =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.m
Answerwidth =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the
Answerwidth =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m
Answerwidth =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area
Answerwidth =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area
Answerwidth =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25
Answerwidth =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25=575−25
Answerwidth =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25=575−25=550sqm
Answerwidth =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25=575−25=550sqm
Answerwidth =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25=575−25=550sqm
Answerwidth =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25=575−25=550sqm cost of the construction per sq.m =Rs.105
Answerwidth =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25=575−25=550sqm cost of the construction per sq.m =Rs.105total cost =550×105=Rs 57750
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