Question

A garden hose having an internal diameter of 2 cm is connected to a lawn sprinkler that consist of an encloser with 12 holes each 0.2cm in diameter if yhe water in the hose has a speed 1.2 meter per second at what speed does it leaves the sprinkler holes

Answer 1

Answer:

its speed is about to be 50km/hr

Answer 2

The speed when it leaves the sprinkler holes is 10 m/s.

Explanation:

Given that,

Diameter D= 2 cm

Number of holes = 12

Diameter of each hole d= 1.2 m

Speed v= 1.2 m/s

Let v be the velocity of water flowing out of each hole.

We need to calculate the speed when it leaves the sprinkler holes

Using formula of volume

Volume of the water crossing hose per second is equal to the volume of the water leaving out per second through holes

$A\times v=A'\times v'$

$\dfrac{\pi\times D^2}{4}\times v=n\pi\times\dfrac{d^2}{4}\times v'$

$v'=\dfrac{D^2v}{nd^2}$

Put the value into the formula

$v=\dfrac{2^2\times1.2}{12\times(0.2)^2}$

$v=10\ m/s$

Hence, The speed when it leaves the sprinkler holes is 10 m/s.

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Topic :

https://brainly.in/question/2162817