Math, asked by hirensahni5098, 16 hours ago

A garden inside a park has the shape of a trapezoid its bases are 10 meters and 16 meters The perpendicular distance between these bases is 12 meters What is the area of the garden

Answers

Answered by RvChaudharY50
18

Given :- A garden inside a park has the shape of a trapezoid its bases are 10 meters and 16 meters The perpendicular distance between these bases is 12 meters

To Find :- What is the area of the garden ?

Solution :-

we have,

→ Base lengths = Parallel sides length = 10 m and 16 m

and,

→ The perpendicular distance between these bases = Height of trapezium = 12 m .

so,

→ Area of Trapezium shaped garden = (1/2) * sum of parallel sides * Height

putting values we get,

→ Area of Trapezium shaped garden = (1/2) * (10 + 16) * 12

→ Area of Trapezium shaped garden = (1/2) * 26 * 12

→ Area of Trapezium shaped garden = 26 * 6

→ Area of Trapezium shaped garden = 156 (Ans.)

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Answered by bhagyashreechowdhury
13

Given:

A garden inside a park has the shape of a trapezoid its bases are 10 meters and 16 meters The perpendicular distance between these bases is 12 meters What is the area of the garden?

To find:

The area of the garden

Solution:

To solve the above-given problem we will use the formula of the area of a trapezium which is as follows:

\boxed{\bold{Area \:of\:a\:trapezium = \frac{1}{2}\times [Sum \:of\:parallel\:sides] \times [Perpendicular \:height] }}

Here we have,

The two parallel sides of the trapezoidal-shaped garden are 10 m and 16 m.

The perpendicular distance between the 2 parallel sides is 12 meters

Now, on substituting the given values in the formula above, we get

The area of the trapezoidal garden is,

= \frac{1}{2}\times [10 + 16] \times 12

= \frac{1}{2}\times 26 \times 12

= 13 \times 12

= \bold{156\:m^2}

Thus, the area of the garden is → 156 m².

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