Question

a garden is 20 by 16 m in the middle of the garden there is a square cement platform of side 3m find the cost of weding the garden at the rate 7 per square m
​

Answer 1

Given -

• Length of Garden (l) = 20m

• Width of Garden (b) = 16m

• In middle of Garden platform of side = 3m

To find -

• Cost of weeding garden at the rate of ₹7 m²

Solution -

Area of Garden = Length × Breadth

Area of garden = 20 × 16 = 320m²

Area of Square Cemented Platform = (side)²

→ Area of square = (3)²

→ Area of square = 9m²

Now,

Area of Weeding Part of Garden = Area of Garden - Area of square Cemented platform

→ 320 − 9 m

→ 311m²

Cost of Weeding Garden at rate = 1m² = ₹7

→ 311m² = 7 × 311

→ ₹2177

$\therefore$ Cost of weeding the garden at the rate of ₹7 m² is ₹2177

______________________________________

Answer 2

Answer:

Given :-

• Length of garden = 20 m
• Breadth of garden = 16 m
• Side of cement platform = 3 m
• Cost of weding garden per m = ₹7

To Find :-

Total cost of weding

Solution :-

Firstly we will find area of cement platform and area of garden

$\huge \tt \: Area \small \: garden \huge \: = 2(l + b)$

$\huge \tt \: Area \small \: garden \huge \: = 2(20 + 16$

$\huge \tt \: Area \small \: garden \huge \: = 2(36)$

$\huge \mathfrak {Area \: of \: garden \: = 72 \: m}$

Now,

Let's find area of cement platform

$\huge \tt \: Area \small \: platform \huge \: = {s}^{2}$

$\huge \tt \:Area \small \: platform \huge = {3}^{2}$

$\huge \mathfrak {Area \: of \: platform = 9m}$

Let's find the area to be platformed

$\huge \tt \: Area \small \: garden \huge \: - Area \small \: platform$

$\huge \bf320 - 9$

$\huge {\green {\bf {Platformed \: area = 321 \: m}}}$

$\huge \tt \: Total \: cost \: = 311 \times 7$

$\huge \bf \star\: Total \: cost \: = ₹2177 \:$

Learn More :-

Perimeter of rectangle = 2(l+b)

Area of rectangle = l × b

Perimeter of square = 4s

Area of square = side²

Volume of Cuboid = l × b × h

Volume of cube = a³ or a × a × a