Math, asked by Honey1805, 3 months ago

A garden is 200 m long and 160 m broad. In its middle there is a circular tank of
radius 28 m. Find the cost of covering the remaining portion of the garden with
grass at the rate of 50 paise per sq metre.
28 m.

no spams...​

Answers

Answered by adiraw2580
5

14768 \: rs

Step-by-step explanation:

area \: of \: rectangular \: garden \:  = l \times b \\  = 200 \times 160 \\  = 32000 \:  {m}^{2}  \\ area \: of \: tank \:  = \pi{r}^{2}  \\  =  \frac{22}{7}  \times 28 \times 28 \\  = 88 \times 28 \\  = 2464 \:  {m}^{2}  \\ area \: of \: remaining \: figure = 32000 - 2464 \\  = 29536 \:  {m}^{2}  \\  \\ cost \: of \: covering \: 1 {m}^{2}  = 50  \:  paise  = \frac{50}{100} rs \\ cost \: of \: covering \: 29536 \:  {m}^{2}  =  \frac{50}{100}  \times 29536 \\  =  \frac{1}{2}  \times 29536 \: rs  \\  = 14768 \: rs

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