Question

a garden is 80 m long and 65 m broad . a path of 5 m wide is to be built along its border. find the cost of levelling the path at the rate of $ 5.50 per m2
please give the right answer ​

Answer 1

Answer:

Length of garden =90m Breadth of garden =75m Width of path =5m Outer length =100m(90+5+5) Outer breadth =85m(75+5+5) Area of path = area of outer rectangle - area of inner rectangle ⇒(100⋅85)−(90⋅75) ⇒8500−6750=1750m2 Hence, area of rectangle 1= 1750 m^21 Now, 1hec=2592m2 Area of path in hec=1752592=675 Area of garden in hec=67502592=2.604

Answer 2

Answer:

Area of original garden =90×75=6750 m

2

After path is added around rectangle, new length =90+2×5=100 m

New breadth =75+2×5=85 m

Area of rectangle with path =100×85=8500 m

2

So,

Area of path = Area of rectangle with path − Area of rectangle without path

Area of path =8500−6750

=1750 m

2

We know,

1 m

2

=0.0001 hectare

So,

6750 m

2

=6750×0.0001

=0.675 hectare

Hence area of ground =6750 m

2

=0.675 hectares