Math, asked by bhaskargupta3455, 4 months ago

a garden is 80 metre long and 65 m broad .A path of 5 m wide is to be built along its border .find the cost of leavelling the path at the rate of rupees 5.50 m per square​

Answers

Answered by ss3876991
3

Length of garden =90m Breadth of garden =75m Width of path =5m Outer length =100m(90+5+5) Outer breadth =85m(75+5+5) Area of path = area of outer rectangle - area of inner rectangle ⇒(100⋅85)−(90⋅75) ⇒8500−6750=1750m2 Hence, area of rectangle 1= 1750 m^21 Now, 1hec=2592m2 Area of path in hec=1752592=675 Area of garden in hec=67502592=2.604

Answered by jyotikak873
3

Answer:

7425.00

Step-by-step explanation:

Area of path=(80×65)-(70×55)

=5200-3850

=1350×5.50

=7425.00

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