Math, asked by Aryandamor0004, 4 months ago

A garden is 90m long and 75m broad . A path 5m wide is to built outside and around it. Find the area of the path. Also find the area of the Garden in hectare.

Please Don't Give wrong answer​

Answers

Answered by umeshnirmal04
2

Answer:

Area of original garden =90×75=6750 m

2

After path is added around rectangle, new length =90+2×5=100 m

New breadth =75+2×5=85 m

Area of rectangle with path =100×85=8500 m

2

So,

Area of path = Area of rectangle with path − Area of rectangle without path

Area of path =8500−6750

=1750 m

Answered by Anonymous
39

Given:-

  • Length = 90m
  • Breadth = 75m
  • Wide = 5m

To Find:-

  • Area of Path
  • Area of Garden in Hectare.

Formula to be used:-

• Area of Rectangle = Length × Breadth

• 1 hectare = 10000m²

Solution:-

Area of the Path is 1750m²

Area of the Garden in hectare is 0.675 hectare.

Step By Step Explanation:-

AB = 90 + 5 + 5 = 100m

Here, We + 5 with The Given Value Because of Wide Path Row. And We will Do same with 85m.

BC = 75 + 5 + 5 = 85m.

Area of ABCD = Length × Breadth

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 100 × 85

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 8500m²

Hence, Area of ABCD is 8500m²

PQ = 90m ; QR = 75m

Area of PQRS = Length × Breadth

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 90 × 75

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 6750m²

Area of PQRS is 6750m²

Now, We have to Find the Area of Path , For finding the area of path ! we will Minus (Area of ABCD with Area of PQRS)

Area of Path = Area of ABCD - Area of PQRS

⠀⠀⠀⠀⠀⠀⠀⠀=⠀⠀⠀ 8500 ⠀⠀⠀⠀- ⠀⠀ 6750

⠀⠀⠀⠀⠀⠀⠀⠀= ⠀⠀⠀⠀⠀⠀1750m²

As we Know , 1 hectare = 10000m²

Area of Garden PQRS = \sf\dfrac{6750}{10000}

= 0.675 Hec

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