Math, asked by Harshchacharkar63, 9 months ago

A garden is 90m long and 75m broad. A path 5m wide is to be built outside and around it. Find the area

Answers

Answered by ItzRadhika
41

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Question

  • A garden is 90m long and 75m broad. A path 5m wide is to be built outside and around it. Find the area?

Answer

  • Area of path = 1750m²

Given

  • Length of garden = 90m
  • Breadth = 75m
  • A path 5m wide is to be built outside

To Calculate

  • Area __?

Explanation

Length (l) = 90m

Breadth (b) = 75m

Area of original garden = length ×breadth

➥ 90×75

➥ 6750m²

After path is added around rectangle

New length = 90+2×5

➥ 100m

New Breadth = 75+2×5

➥ 85m

Area of rectangle with path = length × breadth

➥ 100×85

➥ 8500m²

So,

Area of path = Area of rectangle witb path - Area of rectangle without path

Area of path = 8500-6750

➥ 1750m²

\bf\underline{\underline{\orange{HENCE:-}}}

  • Area of path = 1750m²

__________________________________________

Answered by gugan64
20

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Area of path = 1750m²

Given:-

  • Length of garden = 90m

  • Breadth = 75m

  • A path 5m wide is to be built outside

To Find:-

  • Area of the path?

Solution:-

  • Length (l) = 90m
  • Breadth (b) = 75m

Area of original garden = length ×breadth

➥ 90×75

➥ 6750m²

After path is added around rectangle

After path is added around rectangleNew length = 90+2×5

➥ 100m

New Breadth = 75+2×5

➥ 85m

Area of rectangle with path = length × breadth

➥ 100×85

➥ 8500m²

Sothat

  • Area of path = Area of rectangle witb path - Area of rectangle without path

  • Area of path = 8500m² - 6750m²

➥ 1750m²

Additional information:-

  • Perimerer of rectangle : 2×(l + b)

  • Perimeter of square : (4 × S)

  • Area of rectangle : (l × b)

  • Area of square : (S)²

  • Perimeter of triangle : a + b +c

  • ☆Area of triangle : 1/2×h×b

here,

l = length

b = breath

S = Side

(a + b + c) denotes the three side of the triangle.

h = height

b = base

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