a garden is in the form of trapezium whose parallel sides are 40 and 22 M and the perpendicular distance between them is 12m find the area of the garden
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3
area of trapezium
=1/2×sum of length of parallel sides × height
=1/2×(40+22)×12
=1/2×62×12
=31×12
=372 m2
ANSWER
Area is 372 m2
=1/2×sum of length of parallel sides × height
=1/2×(40+22)×12
=1/2×62×12
=31×12
=372 m2
ANSWER
Area is 372 m2
Answered by
1
Area of trapezium= 1/2(a+b)×h
here, a=40m, b=22m, h=12m
Area= 1/2(40+22)×12
=1/2×62×12msq.
=372msq.
here, a=40m, b=22m, h=12m
Area= 1/2(40+22)×12
=1/2×62×12msq.
=372msq.
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