A garden is in the shape of a quadrillateral. The side of garden are 9m, 40m ,28m , 15 m respectively in consecutive order . The angle between first and second side is rectangle .Find the area of garden
Answers
Answered by
0
ANSWER
Let ABCD be a quadrilateral, then
AB=9m,BC=40m,CD=28m,DA=15m & ∠ABC=90
∘
ar□ABCD=ar△ABC+ar△ACD
In △ABC, using Pythagoras theorem,
AC
2
=AB
2
+BC
2
⇒AC=
9
2
+40
2
=
1681
=41m
ar△ABC=
2
1
×AB×BC=
2
1
×9×40=180m
2
ar△ACD=
s(s−a)(s−b)(s−c)
,S=
2
a+b+c
=
2
15+28+41
=42m
=
42(42−15)(42−28)(42−41)
=
42×27×14×1
=126m
2
∴ar□ABCD=180+126=306m
2
hope it will help you
follow me and mark as brainlist
Similar questions