Question

A garden is in the shape of rectangle of length 100m and breath 60m .a path of width 3m is left all around inside the garcen for the flower bed,. Find the area of path

Answer 1

$\boxed{\text{{given}}}$
AB=100m,BC=60m and the width of the flower bed = 3m
IN RECTANGLE ABCD
Area of rec.ABCD =l×b
= 100×60
=6000m sq.
TO OBTAIN THE WIDTH OF REC. =EFGH
=BC-GH
=60-6 = 54m
TO OBTAIN THE LENGTH OF REC. = EFGH
=100-6 = 94m
then Area of rec EFGH = l×b
= 94×54 = 5076 m sq.
then, THE AREA OF THE FLOWER BED = AREA OF RECTANGLE ABCD - AREA OF RECTANGLE EFGH
=> 6000-5076 =
$\boxed{\text{924 {m \: sq}.}}$

Answer 2

Answer:

AB=100m,BC=60m and the width of the flower bed = 3m

IN RECTANGLE ABCD

Area of rec.ABCD =l×b

= 100×60

=6000m sq.

TO OBTAIN THE WIDTH OF REC. =EFGH

=BC-GH

=60-6 = 54m

TO OBTAIN THE LENGTH OF REC. = EFGH

=100-6 = 94m

then Area of rec EFGH = l×b

= 94×54 = 5076 m sq.

then, THE AREA OF THE FLOWER BED = AREA OF RECTANGLE ABCD - AREA OF RECTANGLE EFGH

=> 6000-5076 =

\boxed{\text{924 {m \: sq}.}}

924 m sq.