Question

A garden is surrounded by a circular path whose inner circumference is 264 m and
the outer circumference is 308 m. Find the width of the path.​

Answer 1

Answer:

width of track is 7 m

race track is in the form of ring whose inner circumference is 264m and outer circumference is 308m.

let radius of inner circumference of ring is r and outer circumference is R. then width of tack must be (R - r).

so, inner circumference = 2πr = 264 m ......(1)

outer circumference = 2πR = 308 m .....(2)

subtracting equation (1) from (2),

2πR - 2πr = 308 - 264

⇒2π(R - r) = 44

⇒2 × 22/7 × width of track = 44

⇒ width of track = 44/(44/7) = 7 m

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