Question

A garden roller is 2m long and has a diameter
of 1.4m. Evaluate the area covered by it in
10revolutions?

plz help me in my exam​

Answer 1

Radius of a garden roller (r) = 1.4 / 2 = 0.7 m

and length of the garden roller (h) = 2 m

∴ Curved surface area of garden roller = 2πrh .

So, the area levelled of a garden roller in one revolution is 8.8 m2.

Now, area levelled of a garden in 5 revolutions = 8.8 x 5= 44m2

Answer 2

Given :-

• Length of the roller = 2 m
• Diameter of the roller = 1.4 m
• Number of revolutions = 10

To Find :-

• The area covered in 10 revolutions.

Solution :-

• Radius = Diameter/2

Where,

• R = Radius
• D = Diameter

Substituting their values,

⟶ R = 1.4/2

⟶ R = 0.7 m

Area covered = CSA of the roller

Area covered in 10 revolution = 10 × 2πrh

= 10 × 2 × 22/7 × 0.7 × 2

= 20 × 30.8/7

= 20 × 4.4

= 88 sq. m

Therefore, the area covered in 10 revolution is 88 sq. m.