a garden roller is 2m wide and has diameter 1.4 m in how many revolutions will it level a field 24 m by 11 m
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✰✰|| Given ||✰✰
- width of roller = 2m
- diameter of roller = 1.4m
- dimensions of field = 24m × 11m
✰✰|| To Find ||✰✰
- radius of roller
- curved surface of roller
- area of field
- No. of revolution roller take
✪|| Solution ||✪
diameter = 2 × radius
1.4 m = 2 × radius
radius = 1.4m/2
radius = 0.7m
curved surface area of roller = 2π × r × width
→ curved surface area of roller = 2 × 22/7 × 0.7m × 2m
→ curved surface area of roller = 44/7 × 0.7m × 2m
→ curved surface area of roller = 44 × 0.1 m × 2m
→ curved surface area of roller = 4.4m × 2m
→ curved surface area of roller = 8.8m²
area of field = 24m × 11m
→ area of field = 264m²
No. of revolution = 264m² ÷ 8.8m²
→ No. of revolution = 264 ÷ 8.8
→ No. of revolution = 30
No. of revolution roller take is 30.
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