Question

A garden roller whose length is 3 m long and whose diameter is 2.8 m is rolled to level a garden. How much area will it cover in 8 revolutions?

Answer 1

Answer:

• A garden roller will cover 211.2 m² of area in 8 revolutions.

Step-by-step explanation:

Given that:

• A garden roller whose length is 3 m long and whose diameter is 2.8 m is rolled to level a garden.

To Find:

• How much area will it cover in 8 revolutions?

Formula used:

• CSA of cylinder = 2πRh

Where,

• CSA = Area covered by roller in one revolution
• R = Radius of roller = 2.8/2 = 1.4 m
• h = Length of roller = 3 m

Finding the area covered by roller in one revolution:

⟶ CSA = 2 × 22/7 × 1.4 × 3

⟶ CSA = (2 × 22 × 1.4 × 3)/7

⟶ CSA = 184.8/7

⟶ CSA = 26.4

∴ Area covered by roller in one revolution = 26.4 m²

Finding the area covered by roller in 8 revolutions:

• One revolution = 26.4 m²
• 8 revolutions = (8 × 26.4) = 211.2 m²

Hence,

• Area covered by roller in 8 revolutions = 211.2 m²

Answer 2

Answer:

Given :-

A garden roller whose length is 3 m long and whose diameter is 2.8 m is rolled to level a garden

To Find :-

How much area will it cover in 8 revolutions?

Solution :-

We know that

CSA = 2πrh

CSA = 2 × 22/7 × 2.8/2 × 3

CSA = 44/7 × 1.4 × 3

CSA = 44 × 0.2 × 3

CSA = 44 × 0.6

CSA = 26.4 m²

Now

Area covered = 8 × 26.4

Area covered = 211.20 m²