Math, asked by vaibhavthenua24, 10 months ago

a gardener has 1000 plants he want to plant these in a such a way that the number of rows and the number of columns remains same find the minimum numbers of plants he had more for this​

Answers

Answered by Vamprixussa
0

Hello mate,

Here is your answer,

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If the number of rows

and number of columns remain same (equal) then the total number of trees will be

in the form of perfect square (x² )

As 1000 is not a perfect square, we first  need to check for a perfect

square above and nearest to 1000. 

[solution is in the attachment]

So , the gardener  needs to add 24 more trees that the number of rows and  columns remain same.

=======================================

HOPE THIS HELPS YOUU :)

AND STAY BLESSED.


vaibhavthenua24: How
Answered by Anonymous
1

It is given that the gardener has 1000 plants. The number of rows and the number of columns is the same. We have to find the number of more plants that should be there, so that when the gardener plants them, the number of rows and columns are same. That is, the number which should be added to 1000 to make it a perfect square has to be calculated.

The square root of 1000 can be calculated by long division method as in the link

The remainder is 39. It represents that the square of 31 is less than 1000.

The next number is 32 and 322 = 1024

Hence, number to be added to 1000 to make it a perfect square = 322 − 1000 = 1024 − 1000 = 24

Thus, the required number of plants is 24.

Attachments:

rihansabri208: from where you get 322 can tell it
rihansabri208: Mmm this is right
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