Math, asked by murtazapetiwalla53, 9 months ago

A Gardener has 6203 plants. He wants to plant this in such a way that the number of rows and the number of columns remain the same. Help the Gardner to find the minimum number of plants he needs more for this. Answer with explanation

Answers

Answered by tiana09k
1

Answer:

2333.33333333

Step-by-step explanation:

?? I'd only know

Answered by shettysarvesh456
3

Answer:

38 Plants

Step-by-step explanation:

Let the total no. of rows = x

since the gardener wants  No.of rows = No.of Columns

therefore Total No. columns = x

Let No.of rows be = 3

Therefore No.of Columns= 3

Total No of Plants in garden =No.of rows x No.of Columns

                                               = 3 x 3

                                                = 9

Therefore we got to know

Total No of Plants in garden =No.of rows x No.of Columns

since  No.of rows = No.of Columns= x

Therefore,

Total No of Plants in garden=x*x= x^2

Current plants are 6203

here 6203 is not a perfect square

We have to add plants and cannot subtract to get perfect square(since in question)

6084 <6203< 7744  

78^2 < 6203 < 88^2 (It means it lies between 78-79)

78^2=6084 < 6203

79^2= 6241 > 6203

Since they have ask minimum number we select 79

Now let x=79

Now, Total No. of plants = 79 * 79

                               = 6241

And we have 6203 plant

So, No. of plant required = Total No. of plants - Current Available Plants

                                         = 6241 - 6203

                                         = 38

 

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