Question

a gardener has 780 plants he wants to plant in such a way that number of rows & columns are same find the minimum numbers of plants he needs move for this​

Answer 1

Answer:

The minimum number of plants he needs more is 4.

Step-by-step explanation:

Let the number of rows be x and the number of columns also be x

Then, the number of plants = x * x = x^2

According to question

x^2 = 780

x = $\sqrt780$

After finding the square root of 780 using long division method, we see that we get a remainder of 51 and quotient as 27. This shows that the square of 27 is less than 780. Next number = 28 and 28^2 = 784

Thus, number to be added = 784-780 = 4

Therefore, The minimum number of plants he needs more is 4.

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