Math, asked by GODAMBASSA1234, 6 months ago

A gardener has to put double fence all around the triangular field of side 120m, 80m and 60m . In the middle of each side there is a gate of width 10 m . Find the rate of fencing at the rate of rs. 6/m.
guys it is urgent please help​

Answers

Answered by rangapranav
1

Answer:

Step-by-step explanation:

A gardener has to put a double fence all around a triangular path with sides 120m, 80m and 60m. In the middle of each side there is a gate of width 10m. Therefore , the length of the wire needed for the fence is 460 m

In the middle of each side there is a gate of width 10m.

The perimeter of triangle = Sum of all sides

                                          = 120+80+60 = 260 m

Now , the length of wire needed for fence =  2 x [Perimeter of triangle - 3(10)]

= 2 x(260-30) = 2 x (230) = 460 m

Therefore , the length of the wire needed for the fence is 460 m.  PLS MARK ME AS BRAINLIEST

Answered by radhi83
0

Answer:

The cost of fencing is 2,760 rupees.

Step-by-step explanation:

The perimeter of triangle= S1+S2+S3

 = 120+80+60

 = 260m

They left 10m gap on each side. So, three sides is 30m.

 = 260-30

 = 230m

The perimeter to fence is 230m.

Cost for fencing 1m= 6 rupees

Cost for double fencing 230m= 230×6×2

 = 2760 rupees

Similar questions