Physics, asked by shwetachoudhary310, 1 year ago

A gardener waters plants by a pipe of cross section 1mm^2. The water comes out at the rate of 100cc/s. The reaction force exerted on the hand of gardener is
a) 10N b) 100N c) 1000N d) 500N

Answers

Answered by gadakhsanket
131

Hey Dear,

◆ Answer -

(a) F = 10 N

◆ Explaination -

# Given -

A = 1 mm² = 10^-6 m²

V/t = 100 cc/s = 10^-4 cu.m/s

# Solution -

Reaction force exerted by water on gardeners hand -

F = m × a

F = m × v/t

F = d × V × s/t²

F = d × V × (V/A) / t²

F = d × (V/t)² / A

Now substitute values -

F = 1000 × (10^-4)² / 10^-6

F = 10 N

Therefore, Reaction force exerted by water on gardeners hand is 10 N.

Thanks dear...

Answered by ganeshank1997
14

here's your answer hope it helps....

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