Question

A gardener waters the plants by a pipe of diameter 1 mm. The water comes out from the pipe atthe rate of 10 cm3/sec. The reactionary force exerted on the hand of the gardener is?

Answer 1

Diameter of pipe- 1mm Radius will be, r-0.5mm- 0.0005m Area of the cross section of pipe is Λ-πr² Density of water is, D- 1000 kg/m³ Volume of water coming out per second is, 10 cm³/s- 10¯⁵m³/s Mass of water coming out per second is, dm/dt- density x volume/sec (1000)( 10¯⁵) Kg/s - 10¯² Kg/s dm/dt- 10¯² Kg/s Now, Volume/sec- Area x Velocity Λ-πr² 3.14 x (0.0005²) 10¯⁵- (3.14) x(0.0005²) x v V – 12.74 m/s Now, Force- change in momentum/sec f- d (mv)/dt f- v (dm/dt), velocity, v is constant f- (12.74)( 10¯²) f- 0.1274 N Diameter of pipe- 1mm

Radius will be, r-0.5mm- 0.0005m

Area of the cross section of pipe is Λ-πr²

Density of water is, D- 1000 kg/m³

Volume of water coming out per second is, 10 cm³/s-

10¯⁵m³/s

Mass of water coming out per second is,

dm/dt- density x volume/sec (1000)( 10¯⁵) Kg/s - 10¯² Kg/s dm/dt- 10¯² Kg/s

Now,

Volume/sec- Area x Velocity

Λ-πr²

3.14 x (0.0005²)

10¯⁵- (3.14) x(0.0005²) x v

V – 12.74 m/s

 Now,

 Force- change in momentum/sec

f- d (mv)/dt

f- v (dm/dt), velocity, v is constant

f- (12.74)( 10¯²)

f- 0.1274 N

Answer 2

Explanation:

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