a gardner waters plant by a pipe of diameter1mm the water comes out at the rate of 10cm³/sec the reactionary force exerted on the hand of the gardner is
Answers
Answered by
2
Are podhe ko pani pilana bohat acha Kam kiya
Well done keep it up
Together we will save environment
Pilao pani par bohat zyada mat pilana kyouki
Save water and water will save you
Please mark it as brainleast
Well done keep it up
Together we will save environment
Pilao pani par bohat zyada mat pilana kyouki
Save water and water will save you
Please mark it as brainleast
Answered by
0
nohere you need to apply Newton's second law.
when gardener starts watering at a rate of 10cm3/s i.e,force=d/dt(mass)*velocity +((mass)*d/dt(velocity)).
but in this case it seems that velocity of water seems to be constant because the rate of flow is constant and area is constant too....
Now,force=d/dt(mass)*velocity
area*velocity=rate of flow of volume per unit time(at opening end of pipe).
so,now the rate of flow of mass per unit time=density*velocity*area
i.e,d/dt(mass)=density*rate of flow
now force=density*rate of flow*velocity
now,you should substitute the given value here.I am leaving that part to you.
hope this helps.If you did not get it then you can ask me again.
when gardener starts watering at a rate of 10cm3/s i.e,force=d/dt(mass)*velocity +((mass)*d/dt(velocity)).
but in this case it seems that velocity of water seems to be constant because the rate of flow is constant and area is constant too....
Now,force=d/dt(mass)*velocity
area*velocity=rate of flow of volume per unit time(at opening end of pipe).
so,now the rate of flow of mass per unit time=density*velocity*area
i.e,d/dt(mass)=density*rate of flow
now force=density*rate of flow*velocity
now,you should substitute the given value here.I am leaving that part to you.
hope this helps.If you did not get it then you can ask me again.
Similar questions