A garrison has sufficient provisions for 240 men for 12 days. If the number of men is reduced by 60, how many days will the provisions last ?
() 9 () 16 () 10
Answers
Answer:
9
Step-by-step explanation:
According to the information provided in the question it is given as
A garrison has sufficient provisions for 240 men for 12 days. If the number of men is reduced by 60,
We need to find the how many days will the provisions last
If number of man reduced by 60 then remaining men is equal to the Difference between starting numbers and reduce numbers as follows
240- 60 = 180 men
For solving this question we make a simple equation as follows
Let us assume x is the number of days for reduce by 60
240men = 12 days
180 men =x
By simple cross multiplication we get the value of x
[tex]240x =12\times 180\\ 240x= 2160\\ x=\frac{2160}{240} \\ [/tex]
Reducing zeros on both numerator as well as denominator
[tex]x=\frac{216}{24} \\ x = 9\\ [/tex]
Hence 9 days the provision last after reducing 60 men
Option () 9 is correct
Answer:
Option (b) 16
Step-by-step explanation:
Given that a garrison has sufficient provisions for 240 men for 12 days. If the number of men is reduced by 60. We need to find out that for how many days will the provisions last.
To solve this problem use the inverse variation (It is the relationship between variables. Furthermore if one variable increases then the other one decreases; to make the resultant or product constant. (xy = k; where k is constant)) method.
Let's say that number of days be x for 60 men.
For 240 men = 12 days
For 60 men = x days
But wait! Read the question carefully. "a garrison has sufficient provisions for 240 men for 12 days. If the number of men is reduced by 60."
Number of men reduced by 60 out of total men. So, the number of men reduced = 180 men. (240 - 60)
So, assume that number of days be x for 180 men.
Therefore,
→ x1y1 = x2y2
Substitute the values,
→ 240(12) = 180(x)
→ 2880 = 180x
→ 2880/180 = x
→ 16 = x
→ x = 16 days
Hence, the provisions will last for 16 days.