A garrison of 120 men has provision for 30 days.At the end of 5 days, 5 more people joined them.How many days can they sustain on the remaining provision.
Please help me as soon as possible.
It is question of inverse variation from DAV class-8 book
Answers
Answered by
80
Answer:
if men-120 then days-25
if men-125 then days-x
this is a case of inverse variation....
120*25=125*x
x=120*25/125
x=24 days ANSWER
HOPE IT HELPS YOU
Answered by
5
Step-by-step explanation:
given :-
- garrison of 120 men has provision for 30 days.
- At the end of 5 days, 5 more people joined .
To Find :-
- How many days can they sustain on the remaining provision
the provision for 1 men would sustain for. 120 × 30 = 3600 days.
Supposed the last number is x
120 × 30 = 120 × 5+125 × x
(120 × 30) - (120 × 5)= 125x
3600 - 600 = 125x
3000 = 125x
x. = 3000/125
x = 120/5
X = 24
Hence the provision would remain for more 24 days.
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