Question

A garrison of 120 men has provision for 30 days. At the end of five days, five more
men joined them. How many days can they sustain on the remaining provision?​

Answer 1

Given :

• A garrison of 120 men has provision for 30 days.

• At the end of five days, five more men joined them.

To find :

• They can sustain on the remaining provision =?

Step-by-step explanation :

5 extra men join then the total men = 120 + 5 = 125

Let, after the joining of 5 men (after 5 days), It took x days to sustain on the remaining provision.

According to the question :

➮ 120 × 30 = 120 × 5 + 125 × x

➮ (120 × 30) − (120 × 5) = 125x

➮ 120 (30 − 5) = 125x

➮ 120 × 25 = 125x

➮ 120 = 5x

➮ x = 24

Therefore, We got the value of, x = 24.

Hence, they sustain on the remaining provision = 24 days.

Answer 2

Question:

A garrison of 120 men has provision for 30 days .

At the end of five days , Five more men joined them . How many days can they sustain on the remaining provision?

Answer:

The men can sustain on remaining provision for

24 days

Given :

➛A garrison of 120 men has provision for 30 days.

➛At the end of five days, five more men joined them.

To find :

The number of days the men can sustain on remaining provision.

Solution:

We are given ,

➛A garrison of 120 men has provision for 30 days.

➛At the end of five days, five more men joined them.

⛬ Total men join are : 120 + 5 ➻ 125

Let , After joining of 5 more men after 5 days they sustain on remaining provision for m days .

Hence ,

: ➡ 120 × 30 = (120 × 5) + 125 × m

: ➡ (120 × 30) − (120 × 5) = 125 × m

: ➡ 120 (30 − 5) = 125m

: ➡ 120 × 25 = 125m

:➡ 120 = 5m

:➡ m = 24

⛬ The men sustain on the remaining provision = 24 days.