a Garrison of 120 men has provision for 30 days at the end of 5 days 5 more men joined them how many days can they sustain on the remaining provision
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Answer:
no of men- 120
no of days- 30
at the end of five days= 30-5= 25
5 men joined=120+5=125
no. of men=120,125
no. of days=30,x
more men less days
it is the case of inverse variation.
= 120* 35 = 125 * x
=x=120*25/125
= x=24 days.
ur answer is 24 days
plzzz mark it's brainlist
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