Math, asked by vikas6765, 1 year ago

a garrison of 200 men had provision of food for 45 day .a reinforcement of 100 men arrived . find the number of days which the food last.

Answers

Answered by yashbelekar
0
men --day
200--45
100--x



= 200×45
=9000
=9000



x=9000÷100
=90
x=99


therefore,100men had provision of food for 90 days
Answered by rohitrathee30
0
For 200 men provision of food = 45 days
For 1 men provision of food=45/200
For 100 men provision of food=45/200×100
=45/2=22.5 days
Means 22 and half days.

rohitrathee30: Like my answer.
rohitrathee30: like my answer it is right.
vikas6765: no
rohitrathee30: what is answer and where is problem.
vikas6765: 30 days answer
rohitrathee30: not you tell me how it come.
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