a garrison of 200 men had provision of food for 45 day .a reinforcement of 100 men arrived . find the number of days which the food last.
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men --day
200--45
100--x
= 200×45
=9000
=9000
x=9000÷100
=90
x=99
therefore,100men had provision of food for 90 days
200--45
100--x
= 200×45
=9000
=9000
x=9000÷100
=90
x=99
therefore,100men had provision of food for 90 days
Answered by
0
For 200 men provision of food = 45 days
For 1 men provision of food=45/200
For 100 men provision of food=45/200×100
=45/2=22.5 days
Means 22 and half days.
For 1 men provision of food=45/200
For 100 men provision of food=45/200×100
=45/2=22.5 days
Means 22 and half days.
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