a garrison of 240 men has provison for food for 30 days at the end of 5 days 10 more men joined them. How many days can they sustain on the remaining provision .please do it on notebook
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no. of men=240
no. of day=30
at the of five day
therefore total day =30-5is equal to 25 day
At the end five day 10more man join them.
240+10=250.
let required no. of day be x
no. of men=240,250
no. of day= 25 ,x
it is a case of inverse variation
therefore for inverse variation,xy=k
therefore 240×25 = 250×x
therefore x = 240×25/250
therefore X =24.
Number of days =24days
no. of day=30
at the of five day
therefore total day =30-5is equal to 25 day
At the end five day 10more man join them.
240+10=250.
let required no. of day be x
no. of men=240,250
no. of day= 25 ,x
it is a case of inverse variation
therefore for inverse variation,xy=k
therefore 240×25 = 250×x
therefore x = 240×25/250
therefore X =24.
Number of days =24days
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