Math, asked by Dida885, 11 months ago

A garrison of 3300 men has provisions for 32 days, when given at a rate of 850 grams per head. At the end of 7 days a reinforcement arrives and it was found that now the provisions will last 8 days less, when given at the rate of 825 grams per head. How, many more men can it feed?



a.1540 men



b.1250 men



c.1700 men



d.250 men

Answers

Answered by amitnrw
12

Answer:

1700 men

Step-by-step explanation:

A garrison of 3300 men has provisions for 32 days, when given at a rate of 850 grams per head. At the end of 7 days a reinforcement arrives and it was found that now the provisions will last 8 days less, when given at the rate of 825 grams per head

Total food available = 3300 * 32 * 850

Food consumed in 7 days = 3300 * 7 * 850

Food remained after 7 days = 3300 * 32 * 850  - 3300 * 7 * 850

= 3300 * 25 * 850

Remaining days = 32 - 7 = 25

Food will survive now 8 days less

so remaining Days = 25 - 8 = 17

Let say Reinforcement of x people came

so total people = (3300 + x)

Requirement for (3300 + x) for 17 days per 825 grams

(3300 + x) * 17 * 825 = 3300 * 25 * 850

=> (3300 + x) = 3300 * 25 * 850 / (17 * 825)

=>   (3300 + x) = 3300 * 1 * 50 /  33

=> 3300 + x = 5000

=> x = 1700

1700 more men can be feeded

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