A garrison of 900 men had provisions for 42 days. However a reinforcement of 500 men arrived. For how many days will the food last now?
Answers
Answered by
250
Solution :-
Let the required number of days be x
More men less days - It is an inverse variation.
⇒ 1400 : 900 : : 42 : x
⇒ 1400x = 900*42
⇒ x = 37800/1400
⇒ = 27 days
So, the food will last for 27 days, when a reinforcement of 500 men arrived.
Answer.
Let the required number of days be x
More men less days - It is an inverse variation.
⇒ 1400 : 900 : : 42 : x
⇒ 1400x = 900*42
⇒ x = 37800/1400
⇒ = 27 days
So, the food will last for 27 days, when a reinforcement of 500 men arrived.
Answer.
Answered by
98
Given:
900 men has food provisions for 42 days.
Let number of men [ x ] = 900(x1) , 1400(x2) (500 more men arrived)
number of days [ y ] = 42(y1) , y2
If there are more men, food provisions for them will be there for less days.
So, it is case of an inverse proportion.
x1y1 = x2y2
900 × 42 = 1400 × y2
y2 = 900 ×42 / 1400
y2= 9 × 42 / 14
y2= 9 ×3
y2= 27 days
Hence, the food will last for 27 days, when a reinforcement of 500 men arrived.
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Hope this will help you...
900 men has food provisions for 42 days.
Let number of men [ x ] = 900(x1) , 1400(x2) (500 more men arrived)
number of days [ y ] = 42(y1) , y2
If there are more men, food provisions for them will be there for less days.
So, it is case of an inverse proportion.
x1y1 = x2y2
900 × 42 = 1400 × y2
y2 = 900 ×42 / 1400
y2= 9 × 42 / 14
y2= 9 ×3
y2= 27 days
Hence, the food will last for 27 days, when a reinforcement of 500 men arrived.
==================================================================
Hope this will help you...
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