Question

A gas A having molecular weight 4diffuses twice as fast as the gas B the molecular weight of gas B is

Answer 1

FORMULA

• Diffusion is inversely proportional to square root of molecular weight. Hence, rate of diffusion (d) can be compared as

$\frac{d1}{d2} = \sqrt{ \frac{m2}{m1} }$

SOLUTIONS

Given, d1 = 2d2.

Hence,

$\frac{d1}{d2} = 2$

Now,

Applying the formula

$\frac{d1}{d2} = \sqrt{ \frac{m2}{m1} } \\ = > 2 = \sqrt{ \frac{m2}{4} } \\ squaring \: both \: sides \\ = > 4 = \frac{m2}{4} \\ = > m2 = 16$

Hence , molar mass of second gas is 16 gram.