Question

A gas absorb 2000j of heat and expands against on internal pressure of 2 atm from a of 0.5 L to 10.5 L . calculate change in internal energy

Answer 1

internal energy =joules ×2at÷0.5+10.5divides 2 and finally answer is 63.23 joules energy




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Answer 2

Change in internal energy is -26 Joules

Explanation:

According to first law of thermodynamics:

$\Delta E=q+w$

$\Delta E$=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system=$-P\Delta V$  {Work is done by the system as the final volume is greater than initial volume and is negative}

w =$-2atm\times (10.5-0.5)L=-20Latm=-2026Joules$  {1Latm=101.3J}

q = +2000J   {Heat absorbed by the system is positive}

$\Delta E=2000-2026=-26J$

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