Question

A gas absorbs 120 J of heat and expands against the external pressure of 1.10 from a volume of 0.5 L to 2.0 L .What is the change in internal energy?(1Latm=101.3J)​

Answer 1

Answer:

We know that, delta U = q + W Here, we have q=120 J W=-P(delta V) negative sign due to work done by the system delta V= 2.0 - 0.5 = 1.5 L Therefore, delta U = q - P(delta V) =120 - 1.10(1.5) =120 - 1.65 =118.35 J

Answer 2

Answer:

A gas absorbs 120 J of heat and expands against the external pressure of 1.10 from a volume of 0.5 L to 2.0 L .What is the change in internal energy?(1Latm=101.3J)