Question

A gas absorbs a photon of 355 nm and emits at two wavelengths.If one of the emissions is at 680 nm ,the other is at

Answer 1

Explanation:

From Law of Conservation of energy, energy of absorbed photon must be equal to combined energy of two emitted photons.

ET=E1+E2 .....(1)

where E1 is Energy of first emitted photon emitted and

E2 is Energy of second emitted photon.

Energy

E and wavelength

λ of a photon are related by the equation

E=hc/λ .....(2)

where

h is Planck's constant,

c is velocity of light.

Inserting values from (2) in (1) we get

hc/λT=hc/λ1+hc/λ2

⇒1/λT=1/λ1+1/λ2 ......(3)

Substituting given values in (3) we get

1/355=1/680+1/λ2

⇒1/λ2=1/355−1/680

⇒1/λ2=680−355/(355×680)

⇒λ2=742.77nm