Question

A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emissions is at 680 nm, the other is at: 

Answer 1

HERE IS YOURS SOLUTION;

◆ The energy absorbed by the photon must be equal to combined energy of two emitted photons.

ET=E1+E2 .....(1)

where E1 is Energy of first emitted photon emitted and E2 is Energy of second emitted photon.

◆ Energy E and wavelength λ of a photon are related by the equation

E=hcλ .....(2)

where h is Planck's constant, c is velocity of light.

◆ Inserting values from (2) in (1) we get

hcλT=hcλ1+hcλ2

⇒1λT=1λ1+1λ2 ......(3)

◆ Substituting given values in (3) we get

1355=1680+1λ2

⇒1λ2=1355−1680

⇒1λ2=680−355355×680

⇒λ2=742.77nm

◆ So, the answer is 742.77 nm ◆


HOPE IT HELPS

Answer 2

Answer:According to law of conservation of energy,

hc/355 = hc/680+ hc/λ

Therefore,

(680 − 355)/(355 x 680) =1/λ

λ = 742.77 nm

= 743 nm

Explanation: