Question

A gas absorbs a photon of 355 nm and emits two wavelengths. If one of the emissions is at 680 nm, the other is at :

Answer 1

Answer:

From Law of Conservation of energy, energy of absorbed photon must be equal to combined energy of two emitted photons.

E

T

=

E

1

+

E

2

.....(1)

where

E

1

is Energy of first emitted photon emitted and

E

2

is Energy of second emitted photon.

Energy

E

and wavelength

λ

of a photon are related by the equation

E

=

h

c

λ

.....(2)

where

h

is Planck's constant,

c

is velocity of light.

Inserting values from (2) in (1) we get

h

c

λ

T

=

h

c

λ

1

+

h

c

λ

2

⇒

1

λ

T

=

1

λ

1

+

1

λ

2

......(3