Question

A gas at 25°C has it's temperature raised so that it's volume doubles, pressure remains constant. Find it's final temperature.

1. 273°K 2. 323°K 3. 293°K 4. 300°K

Answer 1

2. 323 k is correct.

Answer 2

Answer:

The final temperature of the gasoline is 323 K or 50°C

Explanation:

From the above question,

The combined gas law to solve this problem, which relates the pressure, volume, and temperature of a gas:          

                    (P1V1)/T1 = (P2V2)/T2

Where P1 and T1 are the preliminary strain and temperature, V1 is the preliminary volume, P2 is the ultimate strain (which stays regular in this case), V2 is the last extent (twice the preliminary volume), and T2 is the last temperature (what we're attempting to find).

Plugging in the given values, we get:

                    (P1V1)/T1 = (P2V2)/T2

                    (P1V1)/298 = (P1*2V1)/T2 [since stress stays constant, we can replacement P1 for P2]

Simplifying, we get:

                    T2 = (P12V1298)/(P1V1)

                    T2 = 2298

                    T2 = 596 K

Converting this to Celsius, we get:

                    T2 = 596 - 273 = 323°C

Therefore, the last temperature of the gasoline is 323 K or 50°C, which is alternative 2.

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