a gas at -33℃ is heated to 127℃ at constant temperature. Calculate the percentage increase in the volume of gas.
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heya friend here's your answer
let initial volume of gas (V1) be x
T1= _33 + 273
=240K
T2=127+273
=400K
V2=?
According to Charlie's law:
V1/T1= V2/T2
therefore by substitution:
V2= (400 × x) / 240
=5x/3
therefore increase in volume=5x/3 - x
=2x/3
therefore % increase in gas=(2x/3x) × 100
= 66 2/3 %(mixed fraction)
hope it helps
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let initial volume of gas (V1) be x
T1= _33 + 273
=240K
T2=127+273
=400K
V2=?
According to Charlie's law:
V1/T1= V2/T2
therefore by substitution:
V2= (400 × x) / 240
=5x/3
therefore increase in volume=5x/3 - x
=2x/3
therefore % increase in gas=(2x/3x) × 100
= 66 2/3 %(mixed fraction)
hope it helps
if u like my answer then pls follow me n mark as brainliest
khushi9d1:
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