Chemistry, asked by singhmasuta2056, 10 months ago

A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :
(1) Z > 1 and attractive forces are dominant
(2) Z > 1 and repulsive forces are dominant
(3) Z <1 and attractive forces are dominant
(4) Z <1 and repulsive forces are dominant

Answers

Answered by Anonymous
8

Hope this helps you

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Attachments:
Answered by rashich1219
3

Z <1 and attractive forces are dominant

Step by step explanation:

  • The compressibility factor describes the external behavior of real gases from the ideal gas.
  • It can be denoted by "Z".
  • The formula -\bold{Z= \frac{PV}{nRT}}
  • And it can also denoted by \bold{Z=\frac{V_{real}}{V_{ideal}}}.
  • Volume of real gases always lower than volume of ideal gases.Hence, Z < 1
  • Therefore, Z <1 and attractive forces are dominant it will be lead to the liquification of gases very easily.

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