Question

A gas at 900°C is cooled until both it's pressure and volume are halved. Calculate it's final temperature​

Answer 1

Answer:

293.25 K

20.25 C°

Explanation:

From the combined gas lass

V ∝ (T/P)

The volume of a given amount of a gas is proportional to the ratio of its kelvin temperature and its presure.

therefore we can say that

(PV)/T = Constant

∴ (P1 V1 ) / T1 = ( P2 V2 ) / T2

⇒ ( P1 V1 ) / 1173 = ( P1/2 V1/2) / T ( Tempersture given 900 C ° , we have to convert it into kelvin )

T2 = 293.25 K

= 20.25 C°

Answer 2

Answer:

Explanation:

From the combined gas lass

V ∝ (T/P)

The volume of a given amount of a gas is proportional to the ratio of its kelvin temperature and its presure.

therefore we can say that

(PV)/T = Constant

∴ (P1 V1 ) / T1 = ( P2 V2 ) / T2

⇒ ( P1 V1 ) / 1173 = ( P1/2 V1/2) / T ( Tempersture given 900 C ° , we have to convert it into kelvin )

T2 = 293.25 K

= 20.25 C°

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