Question

A gas at minus 23 degrees centigrade is heated and allowed to expand at constant pressure its volume on heating changes from 60MLto90ML calculate the final temperature of the gas

Answer 1

102 °C

Explanation:

Given: V₁ = 60 ml = 0.06 L, V₂ = 90 ml = 0.09 L,

T₁ = -23 + 273 = 250.15 K, T₂ = ? K

We know that,

V₁/T₁ = V₂/T₂

T₂ = T₁V₂/V₁

    = 250.15 × 0.09/0.06

    = 375.2 K - 273 = 102 °C