Question

a gas at stp occupies 22.4 litres what will be it's volume if both temparature and ptessure are doubled​

Answer 1

Answer:

volume remain same

22.4L

Explanation:

PV = nRT

P(1)V(1) ÷ P(2)V(2) = n(1) R T(1) ÷ n(2) R T(2)

given

P(2) = 2×P(1)

T(2) = 2×T(1)

V(1) = 22.4 L

V(2) = V {let}

n(1) = n(2)

=> P(1) (22.4) ÷ (2×P(1) V = T(1) ÷ { 2×T(1)}

=> 22.4 ÷ (2V) = 1/2

=> 22.4 = 2V/2

=> V = 22.4