Question

A gas at STP occupies 'V' litres. If its temperature is increased to 546 K and the pressure is decreased to 380 mm of mercury the resultant volume
would be
A.2V
B.4V
C.V/4
D.V only​

Answer 1

The resultant volume would be B. 4V.

Given - Temperature and pressure

Find - Resultant volume

Solution - In this question, ideal gas equation will be used to find the volume. The original and new values will be equated in the formula. At STP, the pressure is 1 atm and temperature is 273 K. New temperature is 546 K. New pressure in atm = 380/760

New pressure = 0.5 atm

The equation to calculate relation between volume.

P1V1/T1 = P2V2/T2

1*V1/273 = 0.5*V2/546

V2 = 546*1*V1/273*0.5

Performing multiplication and division

V2 = 546*V1/136.5

V2 = 4V1

Hence, the resultant volume is B. 4V.

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